Hey I'm new here
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Re: Hey I'm new here
What?! You guys are totally strange. I mean, like, EXTREMELY weird. Weirdos.
Re: Hey I'm new here
So, what's your point?
Re: Hey I'm new here
You obviously didn't understand the joke. Nevermind.
Re: Hey I'm new here
Jokes are funny. That wasn't funny.
Re: Hey I'm new here
Jokes aren't always funny. Like your face. I mean, it's a total joke, but it's just not funny at all. It's kinda depressing. 
(just kidding, please don't take offence. XD)
(just kidding, please don't take offence. XD)
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Hunchman801

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Re: Hey I'm new here
Jokes can be funny or not. It merely depends on your point of view.
Re: Hey I'm new here
Regardless of who is mocked and who is mocking, bad jokes are never funny.
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Hunchman801

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Re: Hey I'm new here
Except for idiots. I included it in the notion of point of view.
Re: Hey I'm new here
Do you think intelligence can be summarized to each one's point of view?
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Hunchman801

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Re: Hey I'm new here
Obviously not, but one's point of view depends on one's intelligence. So if something depends on one's point of view, it also depends on one's intelligence.
Unfortunately, my reasoning would be a sophism if I told you that your statement implies mine; at least mine implies yours.
I would just have to say that one's intelligence depends on one's point of view, but I do not know about it.
Unfortunately, my reasoning would be a sophism if I told you that your statement implies mine; at least mine implies yours.
I would just have to say that one's intelligence depends on one's point of view, but I do not know about it.
Re: Hey I'm new here
If something depends on something else, is the former not supposed to depend on the latter?
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Hunchman801

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Re: Hey I'm new here
It depends on how you define dependance.

Here is an endless circle - which is a pleonasm

Here is an endless circle - which is a pleonasm
Re: Hey I'm new here
Could you please be more accurate?
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Hunchman801

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Re: Hey I'm new here
Just consider an element f of I^J (if I and J are two spaces).
f(X) = Y depends on X.
X = f^(-1)(Y) may depend on Y; but how can you define this dependance is there is no bijection?
f(X) = Y depends on X.
X = f^(-1)(Y) may depend on Y; but how can you define this dependance is there is no bijection?
Re: Hey I'm new here
You get a point. We shall say that X is related to Y for Y depends on X.
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Hunchman801

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Re: Hey I'm new here
By the way, I just made a mistake. The function just needs to be injective, not necessarily bijective.
Re: Hey I'm new here
I had not paid attention to that. Of course, we do not care about nonexistent elements.
Re: Hey I'm new here
This topic is supposed to be about me, not non-existing elements!
Re: Hey I'm new here
But what's the point in posting in it once you are no longer new?
Re: Hey I'm new here
Then lock the topic. 



